★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★
➤微信公众号:山青咏芝(shanqingyongzhi)➤博客园地址:山青咏芝()➤GitHub地址:➤原文地址: ➤如果链接不是山青咏芝的博客园地址,则可能是爬取作者的文章。➤原文已修改更新!强烈建议点击原文地址阅读!支持作者!支持原创!★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★To some string S
, we will perform some replacement operations that replace groups of letters with new ones (not necessarily the same size).
Each replacement operation has 3
parameters: a starting index i
, a source word x
and a target word y
. The rule is that if x
starts at position i
in the originalstring S
, then we will replace that occurrence of x
with y
. If not, we do nothing.
For example, if we have S = "abcd"
and we have some replacement operation i = 2, x = "cd", y = "ffff"
, then because "cd"
starts at position 2
in the original string S
, we will replace it with "ffff"
.
Using another example on S = "abcd"
, if we have both the replacement operation i = 0, x = "ab", y = "eee"
, as well as another replacement operation i = 2, x = "ec", y = "ffff"
, this second operation does nothing because in the original string S[2] = 'c'
, which doesn't match x[0] = 'e'
.
All these operations occur simultaneously. It's guaranteed that there won't be any overlap in replacement: for example, S = "abc", indexes = [0, 1], sources = ["ab","bc"]
is not a valid test case.
Example 1:
Input: S = "abcd", indexes = [0,2], sources = ["a","cd"], targets = ["eee","ffff"]Output: "eeebffff"Explanation: "a" starts at index 0 in S, so it's replaced by "eee"."cd" starts at index 2 in S, so it's replaced by "ffff".
Example 2:
Input: S = "abcd", indexes = [0,2], sources = ["ab","ec"], targets = ["eee","ffff"]Output: "eeecd"Explanation: "ab" starts at index 0 in S, so it's replaced by "eee". "ec" doesn't starts at index 2 in the original S, so we do nothing.
Notes:
0 <= indexes.length = sources.length = targets.length <= 100
0 < indexes[i] < S.length <= 1000
- All characters in given inputs are lowercase letters.
对于某些字符串 S
,我们将执行一些替换操作,用新的字母组替换原有的字母组(不一定大小相同)。
每个替换操作具有 3 个参数:起始索引 i
,源字 x
和目标字 y
。规则是如果 x
从原始字符串 S
中的位置 i
开始,那么我们将用 y
替换出现的 x
。如果没有,我们什么都不做。
举个例子,如果我们有 S = “abcd”
并且我们有一些替换操作 i = 2,x = “cd”,y = “ffff”
,那么因为 “cd”
从原始字符串 S
中的位置 2
开始,我们将用 “ffff”
替换它。
再来看 S = “abcd”
上的另一个例子,如果我们有替换操作 i = 0,x = “ab”,y = “eee”
,以及另一个替换操作 i = 2,x = “ec”,y = “ffff”
,那么第二个操作将不执行任何操作,因为原始字符串中 S[2] = 'c'
,与 x[0] = 'e'
不匹配。
所有这些操作同时发生。保证在替换时不会有任何重叠: S = "abc", indexes = [0, 1], sources = ["ab","bc"]
不是有效的测试用例。
示例 1:
输入:S = "abcd", indexes = [0,2], sources = ["a","cd"], targets = ["eee","ffff"]输出:"eeebffff"解释:"a" 从 S 中的索引 0 开始,所以它被替换为 "eee"。"cd" 从 S 中的索引 2 开始,所以它被替换为 "ffff"。
示例 2:
输入:S = "abcd", indexes = [0,2], sources = ["ab","ec"], targets = ["eee","ffff"]输出:"eeecd"解释:"ab" 从 S 中的索引 0 开始,所以它被替换为 "eee"。"ec" 没有从原始的 S 中的索引 2 开始,所以它没有被替换。
提示:
0 <= indexes.length = sources.length = targets.length <= 100
0 < indexes[i] < S.length <= 1000
- 给定输入中的所有字符都是小写字母。
36ms
1 final class Solution { 2 func findReplaceString(_ S: String, _ indexes: [Int], _ sources: [String], _ targets: [String]) -> String { 3 var dict: [Int: (String, String)] = Dictionary(uniqueKeysWithValues: zip(indexes, zip(sources, targets)) ) 4 var indexes = indexes.sorted(by: >) 5 var S = Array(S) 6 var res = S 7 for index in indexes { 8 let val = dict[index]! 9 let source = Array(val.0)10 let target = Array(val.1)11 if hasOccurence(S, source, index) {12 res.replaceSubrange(index..<(index &+ source.count), with: target)13 }14 }15 return String(res)16 }17 18 @inline(__always) private func hasOccurence(_ S: [Character], _ source: [Character], _ index: Int) -> Bool {19 for i in index..<(index + source.count) {20 if i >= S.count { return false }21 if S[i] != source[i - index] { return false }22 }23 return true24 }25 }
40ms
1 class Solution { 2 struct StringReplaceIndex: Comparable { 3 let index: Int 4 let source: String 5 let target: String 6 7 static func < (lhs: StringReplaceIndex, rhs: StringReplaceIndex) -> Bool { 8 return lhs.index < rhs.index 9 }10 }11 12 func findReplaceString(_ S: String, _ indices: [Int], _ sources: [String], _ targets: [String]) -> String {13 // build the replace indices in sorted order14 var replaceIndices = [StringReplaceIndex]()15 for i in 0..< replaceIndices.count) ? replaceIndices[i+1].index - 1 : S.count - 131 var subString = S.subString(from: startIndex, to: endIndex)32 if subString.hasPrefix(replaceIndices[i].source) {33 subString.removeFirst(replaceIndices[i].source.count)34 subString = replaceIndices[i].target + subString35 }36 result.append(subString)37 }38 return result.reduce("", +)39 } 40 }41 42 extension String {43 44 subscript(i: Int) -> Character {45 get {46 return self[index(startIndex, offsetBy: i)]47 }48 }49 50 func subString(from: Int, to: Int) -> String {51 guard from <= to else {52 return ""53 }54 55 let startIndex = self.index(self.startIndex, offsetBy: from)56 let endIndex = self.index(self.startIndex, offsetBy: to)57 return String(self[startIndex...endIndex])58 }59 60 func subString(from: Int) -> String {61 let startIndex = self.index(self.startIndex, offsetBy: from)62 return String(self.suffix(from: startIndex))63 }64 65 func asciiValues() -> [Int] {66 return Array(self.utf16).map { Int($0) }67 }68 69 mutating func lTrim(_ regex: String = "^\\s+") {70 if let trailingSpacesRange = self.range(of: regex, options: .regularExpression) {71 self.replaceSubrange(trailingSpacesRange, with: "")72 }73 }74 75 mutating func rTrim(_ regex: String = "\\s+$") {76 if let trailingSpacesRange = self.range(of: regex, options: .regularExpression) {77 self.replaceSubrange(trailingSpacesRange, with: "")78 }79 }80 81 func stringByReplacingAt(_ index: Int, with ch: Character) -> String {82 var chars = Array(self)83 chars[index] = ch84 let modifiedString = String(chars)85 return modifiedString86 }87 }
48ms
1 class Solution { 2 private struct ConfirmedReplacement { 3 let start: String.Index 4 let end: String.Index 5 let target: String 6 } 7 8 func findReplaceString(_ S: String, _ indexes: [Int], _ sources: [String], _ targets: [String]) -> String { 9 var confirmedTargets: [ConfirmedReplacement] = []10 //1. confirm11 for i in 0..Bool in24 return rhs.start > lhs.start25 })26 //3. fill string27 var strFragments: [String] = []28 var index = S.startIndex29 for target in confirmedTargets {30 strFragments.append(String(S[index..
1 class Solution { 2 func findReplaceString(_ S: String, _ indexes: [Int], _ sources: [String], _ targets: [String]) -> String { 3 var S = S 4 var v:[[Int]] = [[Int]]() 5 for i in 0..Bool in 10 if a[0] == b[0]11 {12 return a[1] >= b[1]13 }14 else15 {16 return a[0] > b[0]17 }18 })19 for a in v20 {21 var i:Int = a.first!22 var str:String = sources[a[1]]23 var t:String = targets[a[1]]24 if S.subString(i, str.count) == str25 {26 S = S.subString(0, i) + t + S.subString(i + str.count)27 }28 }29 return S30 }31 }32 33 extension String {34 // 截取字符串:从index到结束处35 // - Parameter index: 开始索引36 // - Returns: 子字符串37 func subString(_ index: Int) -> String {38 let theIndex = self.index(self.endIndex, offsetBy: index - self.count)39 return String(self[theIndex.. String {46 let start = self.index(self.startIndex, offsetBy: max(0, begin))47 let end = self.index(self.startIndex, offsetBy: min(self.count, begin + count))48 return String(self[start..